Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
A rather straight forward solution is a two-pass algorithm using counting sort. First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. Could you come up with a one-pass algorithm using only constant space?
可以添加任务,任务包含任务数据,任务延迟触发的等待时间。 在任务到达触发时间点时,自动触发执行此任务。 队列中任务保持先进先出原则:假设 A 任务的触发等待时间为 X,B 任务的触发等待时间为 Y,B 在 A 之后被添加入队列,则 A 的前驱任务执行完成后等待时间 X 后,才执行 A,同理在 A 执行完成后,等待时间 Y,才执行 B。
[12308:000001E565C2F6F0] 14167 ms: Mark-sweep 1395.9 (1425.2) -> 1395.9 (1423.7) MB, 1754.1 / 0.0 ms (+ 0.0 ms in 39 steps since start of marking, biggest step 0.0 ms, walltime since start of marking 1764 ms) (average mu = 0.105, current mu = 0.020) a[12308:000001E565C2F6F0] 14175 ms: Scavenge 1397.3 (1423.7) -> 1397.3 (1425.2) MB, 7.0 / 0.0 ms (average mu = 0.105, current mu = 0.020) allocation failure
$ # Clone the repository to get the example code $ git clone -b v1.25.0 https://github.com/grpc/grpc $ # Navigate to the dynamic codegen "hello, world" Node example: $ cd grpc/examples/node/dynamic_codegen $ # Install the example's dependencies $ npm install
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.