Prolem 104

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

1
2
3
4
5
  3
/ \
9 20
/ \
15 7

return its depth = 3.

key

判断树的深浅,采用

int left = max(root.left);
int right = max(root.right);
return Math.max(left,right) + 1;

//或者简写

return Math.max(max(root.left) + 1, max(root.right) + 1);

进行递归

Runtime: 0 ms, faster than 100.00% of Java online submissions for Maximum Depth of Binary Tree.

Memory Usage: 39.2 MB, less than 94.62% of Java online submissions for Maximum Depth of Binary Tree.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
return max(root);
}
public int max(TreeNode root){
if (root == null) {
return 0;
}
return Math.max(max(root.left) + 1, max(root.right) + 1);
}
}